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submitted 2 months ago by Sunshine@piefed.ca to c/linux@programming.dev

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[–] FizzyOrange@programming.dev 2 points 2 months ago (1 children)

What makes you think it's making a pointer? Nobody said anything about that.

[–] zygo_histo_morpheus@programming.dev 2 points 2 months ago (1 children)

Oh my bad I don't know where I got that from lol

[–] FizzyOrange@programming.dev 3 points 2 months ago

Nw. You're also wrong about endianness. This function would be written exactly the same irrespective of endianness:

uint32_t u16_high_low_to_u32(uint16_t high, uint16_t low) {
  return (high << 16) | low;
}

That is endian agnostic.